(t+10)^2+(t+20)^2=t^2

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Solution for (t+10)^2+(t+20)^2=t^2 equation: 



(t+10)^2+(t+20)^2=t^2

We move all terms to the left:

(t+10)^2+(t+20)^2-(t^2)=0

determiningTheFunctionDomain
-t^2+(t+10)^2+(t+20)^2=0

We add all the numbers together, and all the variables

-1t^2+(t+10)^2+(t+20)^2=0

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